Kuis Brainly07
Tentukan nilai x yang memenuhi persamaan:
![\left[( \sqrt{1} + \sqrt{x + 4} + 4). \frac{1}{3} \right] : \frac{1}{5} = 10](https://tex.z-dn.net/?f=+%5Cleft%5B%28+%5Csqrt%7B1%7D+%2B+%5Csqrt%7Bx+%2B+4%7D+%2B+4%29.+%5Cfrac%7B1%7D%7B3%7D+%5Cright%5D+%3A+%5Cfrac%7B1%7D%7B5%7D+%3D+10 "\left[( \sqrt{1} + \sqrt{x + 4} + 4). \frac{1}{3} \right] : \frac{1}{5} = 10")
Good Luck ^_^
Tentukan nilai x yang memenuhi persamaan:
Good Luck ^_^
Takamori37
Dengan demikian:
![$\begin{align}\left[\left(\sqrt1+\sqrt{x+4}+4\right)\times\frac13\right]:\frac15&=10 \\ \left(\sqrt1+\sqrt{x+4}+4\right)\times\frac13&=10\times\frac15&&\text{(Ubah notasi)} \\ \left(\sqrt1+\sqrt{x+4}+4\right)\times\frac13&=2 \\ \sqrt1+\sqrt{x+4}+4&=2\times3&&\text{(Kalikan silang)} \\ \sqrt1+\sqrt{x+4}+4&=6 \\ 1+\sqrt{x+4}+4&=6 \\ \sqrt{x+4}+5&=6 \\ \sqrt{x+4}&=6-5&&\text{(Pindah ruas)}\\\sqrt{x+4}&=1 \\ x+4&=1^2&&\text{(Kuadratkan kedua ruas)} \\ x+4&=1 \\ x&=1-4&&\text{(Pindah ruas)} \\ x&=-3 \end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D%5Cleft%5B%5Cleft%28%5Csqrt1%2B%5Csqrt%7Bx%2B4%7D%2B4%5Cright%29%5Ctimes%5Cfrac13%5Cright%5D%3A%5Cfrac15%26%3D10+%5C%5C+%5Cleft%28%5Csqrt1%2B%5Csqrt%7Bx%2B4%7D%2B4%5Cright%29%5Ctimes%5Cfrac13%26%3D10%5Ctimes%5Cfrac15%26%26%5Ctext%7B%28Ubah+notasi%29%7D+%5C%5C+%5Cleft%28%5Csqrt1%2B%5Csqrt%7Bx%2B4%7D%2B4%5Cright%29%5Ctimes%5Cfrac13%26%3D2+%5C%5C+%5Csqrt1%2B%5Csqrt%7Bx%2B4%7D%2B4%26%3D2%5Ctimes3%26%26%5Ctext%7B%28Kalikan+silang%29%7D+%5C%5C+%5Csqrt1%2B%5Csqrt%7Bx%2B4%7D%2B4%26%3D6+%5C%5C+1%2B%5Csqrt%7Bx%2B4%7D%2B4%26%3D6+%5C%5C+%5Csqrt%7Bx%2B4%7D%2B5%26%3D6+%5C%5C+%5Csqrt%7Bx%2B4%7D%26%3D6-5%26%26%5Ctext%7B%28Pindah+ruas%29%7D%5C%5C%5Csqrt%7Bx%2B4%7D%26%3D1+%5C%5C+x%2B4%26%3D1%5E2%26%26%5Ctext%7B%28Kuadratkan+kedua+ruas%29%7D+%5C%5C+x%2B4%26%3D1+%5C%5C+x%26%3D1-4%26%26%5Ctext%7B%28Pindah+ruas%29%7D+%5C%5C+x%26%3D-3+%5Cend%7Balign%7D "$\begin{align}\left[\left(\sqrt1+\sqrt{x+4}+4\right)\times\frac13\right]:\frac15&=10 \\ \left(\sqrt1+\sqrt{x+4}+4\right)\times\frac13&=10\times\frac15&&\text{(Ubah notasi)} \\ \left(\sqrt1+\sqrt{x+4}+4\right)\times\frac13&=2 \\ \sqrt1+\sqrt{x+4}+4&=2\times3&&\text{(Kalikan silang)} \\ \sqrt1+\sqrt{x+4}+4&=6 \\ 1+\sqrt{x+4}+4&=6 \\ \sqrt{x+4}+5&=6 \\ \sqrt{x+4}&=6-5&&\text{(Pindah ruas)}\\\sqrt{x+4}&=1 \\ x+4&=1^2&&\text{(Kuadratkan kedua ruas)} \\ x+4&=1 \\ x&=1-4&&\text{(Pindah ruas)} \\ x&=-3 \end{align}")
2 votes
Thanks 6
alvinteguh
![[( 1 + \sqrt{x + 4} + 4) . \frac{1}{3} ] = 10\ $:$\ 5 \\ (1 + \sqrt{x + 4} + 4) . \frac{1}{3} = 2 \\ (5 + \sqrt{x + 4} ) = 2\ $x$\ 3 \\ 5 + \sqrt{x + 4} = 6 \\ \sqrt{x + 4} = 6 - 5 \\ \sqrt{x + 4} = 1 \\ ( \sqrt{x + 4} )^{2} = 1^{2} \\ x + 4 = 1 \\ \boxed{x = 1 - 4 = -3}](https://tex.z-dn.net/?f=%5B%28+1+%2B++%5Csqrt%7Bx+%2B+4%7D+%2B+4%29+.++%5Cfrac%7B1%7D%7B3%7D+%5D+%3D+10%5C+%24%3A%24%5C+5+%5C%5C+%281+%2B++%5Csqrt%7Bx+%2B+4%7D+%2B+4%29+.++%5Cfrac%7B1%7D%7B3%7D+%3D+2+%5C%5C+%285+%2B++%5Csqrt%7Bx+%2B+4%7D+%29+%3D+2%5C+%24x%24%5C+3+%5C%5C+5+%2B++%5Csqrt%7Bx+%2B+4%7D++%3D+6+%5C%5C++%5Csqrt%7Bx+%2B+4%7D+%3D+6+-+5+%5C%5C++%5Csqrt%7Bx+%2B+4%7D+%3D+1+%5C%5C+%28+%5Csqrt%7Bx+%2B+4%7D+%29%5E%7B2%7D++%3D++1%5E%7B2%7D++%5C%5C+x+%2B+4+%3D+1+%5C%5C+%5Cboxed%7Bx+%3D+1+-+4+%3D+-3%7D "[( 1 + \sqrt{x + 4} + 4) . \frac{1}{3} ] = 10\ $:$\ 5 \\ (1 + \sqrt{x + 4} + 4) . \frac{1}{3} = 2 \\ (5 + \sqrt{x + 4} ) = 2\ $x$\ 3 \\ 5 + \sqrt{x + 4} = 6 \\ \sqrt{x + 4} = 6 - 5 \\ \sqrt{x + 4} = 1 \\ ( \sqrt{x + 4} )^{2} = 1^{2} \\ x + 4 = 1 \\ \boxed{x = 1 - 4 = -3}")
2 votes
Thanks 4
