February 2019 0 94 Report
Które wyrazy ciągu (a_{n} ) są równe zeru?

a) a_{n} =  \frac{1}{4} n - \frac{1}{2}
b) a_{n} = 2n + 8
c) a_{n} = n^{2} - 8n + 15
d) a_{n} = n^{2} + 2n - 8
e) a_{n} =  \frac{27 - n^{3} }{n}
f) a_{n} =  \frac{( n^{2}- 4)(9- n^{2}) }{n+6}

Proszę o rozwiązanie z obliczeniami. Dam za to naj.
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.