March 2019 0 64 Report
Ktoś mógłby mi to wytłumaczyć?
Zamień iloczyn na sumę:
a) 3(x-3)
5(y+z)
4(3x-y)
3(4a-c)
-2(7-4n)
b)  \frac{1}{2}(4z+2)
- \frac{1}{3}(6b-3)
0,2(x-5y)
3( \frac{1}{3} a+1)
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