d) 12b × b-1/4 + 14 × b²-2b/21 - b-b²/3= (/= kreska ułamkowa) ZADANIE 6 ZE STRONY 158 Z PODRĘCZNIKA MATEMATYKA Z PLUSEM KLASA 1 . DAJE NAJJJ DLA NAJSZYBSZEGO
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12b * ( b -1 ) :4 + 14 * (b² -2b) :21 - (b -b²) :3 = 12b² - 12b :4 + 14b² - 28b -b + b² : 3 = 12b² - 3b + 14b² - 28b - b + b²/3 = 26b² - 32b + b²/3