Question

1 Usuń niewymierność z mianownika
a) 5/√5
b)3/ 2√2-3
c) 6/ √6
d)2/ 4-3√2
/ kreska ułamkowa
2 Oblicz
a)|1-√3|+|√3-2|
b) |1-√2|+|√2-3|

Answer 1

1a]
5/√5= 5√5/(√5√5)=5√5/5=√5
b]
3/(2√2-3)=3(2√2+3) / (2√2-3)(2√2+3)=(6√2+9)/(8-9)=-(-6√2-9)/-1=
-6√2-9
c]
6/√6=6√6/6=√6
d]
2/(4-3√2)=2(4+3√2) /(4-3√2)(4+3√2)=(8+6√2) / ( 16-18)=-2(-4-3√2) / -2=
-4-3√2
2a]
I 1-√3I + I √3-2 I=√3-1+2-√3=1
B]
I1-√2I +  I√2-3I=√2-1+3-√2=2