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y'= -10-2x
syarat stasioner y'=0
-10-2x=0
-2x=10
x=-5
y'=-10-2x
y"= -2
y"<0 maka disebut titik balik maksimum
untuk x= -5 maka y= 6-10x- = 6-10(-5)-
= 6+50-25=31
maka titik balik maksimum (-5,31)
~maaf klw kurang tepat~~