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a+51b = 105
3+51b = 105
51b = 102
b = 2
u21 = 3+(21-1).2
= 3+40
= 43
U52 = 105
Dit U21 ?
U52 = a + (n-1)b
105 = 3 + (51)b
102 = 51b
B = 2
U21 = a + (n-1)b
U21 = 3 + (20)2
U21 = 3 + 40
U21 = 43