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Kelas 10 MatematikaBab Trigonometri Dasar
Kata Kunci : Koordinat Kutub
(2√3, -2) → x positif dan y negatif, maka di kuadran IV
r = √(x² + y²)
r = √((2√3)² + (-2)²)
r = √(12 + 4)
r = √16
r = 4
tan a = y/x
tan a = -2/(2√3)
tan a = -1/√3
tan a = (-1/3) √3
a = 330°
(4, 330°)