Jawab:
Penjelasan dengan langkah-langkah:
x² - 3x - 4 = 0
a = 1
b = -3
c = -4
x12 = (-b ± √(b² - 4ac))/(2a)
x12 = (- (-3) ± √((-3)² - 4 . 1 . (-4)))/(2 . 1)
x12 = (3 ± √(9 + 16))/2
x12 = (3 ± √25)/2
x12 = (3 ± 5)/2
x1 = (3 + 5)/2
x1 = 8/2
x1 = 4
x2 = (3 - 5)/2
x2 = -2/2
x2 = -1
Maka, x1 = 4 atau x2 = -1
Detail jawaban
Kelas 8
Mapel 2 - Matematika
Bab 6 - Persamaan Kuadrat
Kode kategorisasi : 8.2.6
#backtoschool2019
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Jawab:
Penjelasan dengan langkah-langkah:
x² - 3x - 4 = 0
a = 1
b = -3
c = -4
x12 = (-b ± √(b² - 4ac))/(2a)
x12 = (- (-3) ± √((-3)² - 4 . 1 . (-4)))/(2 . 1)
x12 = (3 ± √(9 + 16))/2
x12 = (3 ± √25)/2
x12 = (3 ± 5)/2
x1 = (3 + 5)/2
x1 = 8/2
x1 = 4
x2 = (3 - 5)/2
x2 = -2/2
x2 = -1
Maka, x1 = 4 atau x2 = -1
Detail jawaban
Kelas 8
Mapel 2 - Matematika
Bab 6 - Persamaan Kuadrat
Kode kategorisasi : 8.2.6
#backtoschool2019