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m.L=4×336000=1344000j
m.c.Δt=4×5×4200=84000j
kalor yg dibutuhkan=1432000j=1432kj
= 4 . 500 .(0- -2)
= 400 j
Q lebur 2 = m.L
= 4 . 336.000
= 1.344.000 j
Q cair 3 = m.Cair.Δt
= 4 . 4200 . (5-0)
= 84.000 j
kalor total Q = Q1+Q2+Q3
= 400 + 1.344.000 + 84.000
= 1.428.400 J
tolong klik bintang