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m = 10 kg
t1 = 25°C
t2 = 100°C
c = 4200 J/kg°C
Dit : Q
Jwb : Δt = t2 - t1 = 100 - 25 = 75°C
Q = m × c × Δt
Q = 10 × 4200 × 75 = 3.150.000 Joule
Semoga membantu, jika ada kekurangan mohon koreksinya~
Δt = t₁ - to
= 100°C - 25°C
= 75°C
c = 4200 J/kg°C
Ditanyakan : Q
Penyelesaian : Q = m . c . Δt
= 10 . 4200 . 75
= 3150000 J
= 3150 kJ
NB : Jika ada yang kurang dipahami, bleh ditanyakan. Semoga membantu :D