Es yang massanya 2 kg dan bersuhu -10' C dicampur dengan air bersuhu 100'C.Suhu keseimbangan 20'C. Berapa gram massa air panas tersebut? (Cair=4200 J/Kg'C, Ces=2100 J/Kg'C, Les=336.000 J/Kg)
tolong BANTUIN....
trisnapramudia
M es.c es.ΔT + m es.L = m air.c air.ΔT 2.2100.30 + 2.336000 = m air.4200.80 126000 + 672000 = 336000. m air m air = 798000/336000 m air =
2.2100.30 + 2.336000 = m air.4200.80
126000 + 672000 = 336000. m air
m air = 798000/336000
m air =