Question

Keliling suatu persegi panjang 28 cm. Jika panjang (x+3) cm dan lebar (2x-4) cm,maka panjang diagonal persegi panjang adalah

Answer 1

Kel = 2*(p+l)
28 = 2*((x+3)+(2x-4))
28 = 2x+6+4x-8
28 = 6x-2
30 = 6x
x = 5
masukan x tadi kedalam persamaan
p = x+3
p = 5+3
p = 8cm

l = 2x-4
l = 2(5)-4
l = 6cm

diagonal = √p²+l²
diagonal = √8²+6²
diagonal = √64+36
diagonal = √100
diagonal = 10cm

jadi, panjang diagonal = 10cm