Andifadhelalfayed
M = 300kg L = 5m A = 0,2cm² - > 2x10⁻⁵m² ΔL = 2,5cm -> 25x10⁻³m
Ditanya E.? F=W W = m.g W = 300.10 W = 3000kg
E = FL / ΔLA
E = 3x10³.5 / 25x10⁻³.2x10⁻⁵ E = 15x10³ / 50x10⁻⁸ E = 0,3x10¹¹ E = 3x10¹⁰ N/m²
65. massa es =100gram suhu es = -10C Volume air -> 200cm³ massa jenis air = 1 g/cm³ m = p.V m = 1.200 m = 200gram massa air 200g suhu 60C kalor lebur = 80kal/g panas jenis es = 0,5 kal/gC panas jenis air = 1 kal/gC
Suhu campuran T..?
Q1 + Q2 + Q3 = Q4 -> es mengalami 3 perubahan suhu
L = 5m
A = 0,2cm² - > 2x10⁻⁵m²
ΔL = 2,5cm -> 25x10⁻³m
Ditanya E.?
F=W
W = m.g
W = 300.10
W = 3000kg
E = FL / ΔLA
E = 3x10³.5 / 25x10⁻³.2x10⁻⁵
E = 15x10³ / 50x10⁻⁸
E = 0,3x10¹¹
E = 3x10¹⁰ N/m²
65.
massa es =100gram
suhu es = -10C
Volume air -> 200cm³
massa jenis air = 1 g/cm³
m = p.V
m = 1.200
m = 200gram
massa air 200g
suhu 60C
kalor lebur = 80kal/g
panas jenis es = 0,5 kal/gC
panas jenis air = 1 kal/gC
Suhu campuran T..?
Q1 + Q2 + Q3 = Q4 -> es mengalami 3 perubahan suhu
(McΔT + ML + McΔT )es= (McΔT)air
100.0,5.(0-(-10) + 100.80 + 100.1.(T-0) = 200.1(60-T)
50(10) + 8000 + 100(T) = 200(60-T)
500 + 8000 + 100T = 12000 - 200T
8500 + 100T = 12000 - 200T
300T = 3500
T= 3500/300
T = 11, 67C