Jml Panjang rusuk
= 4 (p+l+t)
= 4 (50+20+10)
= 4 (80)
= 320 cm
Sisa kawat
= 20m
= 2000 cm - 320 cm
= 1680 cm
(Kalau kerangkanya 1)
Kalau kerangkanya 6
= 320 × 6
= 1920 cm
Sisa = 2000 - 1920
= 80 cm
C.
Semoga membantu:)
kalau 1 balok memerlukan 320 cm kawat (4×p+4×t+4×L) maka 2000cm (20 meter) dibagi 320 = 6 sisa 80. maka sisa dari kawat tsb tersisa 80 cm dari 20 meter (20m)
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Jml Panjang rusuk
= 4 (p+l+t)
= 4 (50+20+10)
= 4 (80)
= 320 cm
Sisa kawat
= 20m
= 2000 cm - 320 cm
= 1680 cm
(Kalau kerangkanya 1)
Kalau kerangkanya 6
= 320 × 6
= 1920 cm
Sisa = 2000 - 1920
= 80 cm
C.
Semoga membantu:)
kalau 1 balok memerlukan 320 cm kawat (4×p+4×t+4×L) maka 2000cm (20 meter) dibagi 320 = 6 sisa 80. maka sisa dari kawat tsb tersisa 80 cm dari 20 meter (20m)