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Verified answer
1.) |K| > 7✐ K > 7
✐ -(K) > 7
K < -7
Sehingga
= {K > 7 atau K < -7}
2.) |3p| = 6
✐ 3p = 6
p = 6/3
p = 2
✐ -(3p) = 6
p = 6/-3
p = -2
Sehingga HP = {-2,2}
3.) |x-2| ≤ |2x+1|
✐ |x - 2| ≤ |2x + 1|
(x - 2)² - (2x + 1)² ≤ 0
(3x - 1)(-x - 3) ≤ 0
x = 1/3 , x = -3
Nilai x yang memenuhi
✐ x ≤ -3 atau x ≥ 1/3
HP = {x ≤ -3 atau x ≥ 1/3}