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uang andre = x
uang budi = y
lalu masukkan persamaan
x + 3y = 64 000
2x + 4y = 100 000
=>
2( x + 3y = 64 000)
1(2x + 4y = 100 000)
2x + 6y = 128 000
2x + 4y = 100 000
trus dieliminasi
2y = 28 000
y = 14 000
lalu disubtitusi ke salah satu persamaan
2x + 4y = 100 000
2x + 4 (14 000) = 100 000
2x + 56 000 = 100 000
2x = 100 000 - 56 000
2x = 44 000
x = 22 000