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maka akar yg lain adalah -2
ingat dalam persm kuadrat berlaku x^2 + (x1 + x2)x + (x1.x2)=0
x = 4,
maka
x² + 2x + c = 0
⇒ 4² + 2(4) + c = 0
⇒ 16 + 8 + c = 0
⇒ 24 + c = 0
⇒ c = -24
maka
x² + 2x + c = 0
⇒ x² + 2x - 24 = 0
⇒ (x + 6)(x- 4) = 0
Sehingga
x + 6 = 0 ⇒ x = -6
x - 4 = 0 ⇒ x = 4
Akar yang lain = -6
Terimakasih semoga membantu