Question

4rpangkat2 × (r pangkat4 ) ×(2r)pangkat 7

Answer 1

4r^2 × r^4 × 2r^7
= 4r^6 × 2r^7
= 8r^13
8r pangkat 13

Answer 2

= 4r² × r⁴ × (2r)^7
= 4 × r² × r⁴ × 2^7 × r^7
= 2² × 2^7 × r² × r⁴ × r^7
= 2^(2+7) × r^(2+4+7)
= 2^9 × r¹³
= (2^9)r¹³
= 512r¹³