Question

Jika x=1 dan y=2 hitunglah
(x³-3x²+x)-(y³-3y²+y)
tlong dibntu yha.. pkek cara..

Answer 1

[(1^3) - (3x1^2) + 1] - [ (2^3) - (3x2^2) + 2]
[1-3+1] - [8-12+2]
(-2+1) - (-4+2)
(-1) - (-2)
(-1) + 2
1

Answer 2

X = 1
y = 2

(x³ - 3x² + x) - (y³ - 3y² + y)

subtitusi nilai x dan y

= ((1)³ - 3(1)² + (1)) - ((2)³ - 3(2)² + 2)
= (1 - 3 + 1) - (8 - 12 + 2)
= (-1) - (-2)
= -1 + 2
= 1