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Verified answer
Dinamika Rotasi• Momen Gaya
F₁ = 10 N
r₁ = 10 cm = 0,1 m
F₂ = 10 N
r₂ = 10 cm = 0,1 m
F₃ = 10 sin 30° = 5 N
r₃ = 20 cm = 0,2 m
∑ τc = __ ?
∑ τc = τ₁ - τ₂ + τ₃
= F₁r₁ - F₂r₂ + F₃r₃
= (10)(0,1) - (10)(0,1) + (5)(0,2)
= 1 Nm