Question

Jika salah satu akar persamaan kuadrat 2x"-(3a-1)x + 5a+4=0 adalah 2 berapakah nilai a???
pleasee... tolong jawabb .. mksh

Answer 1

2X"-(3a-1)X+5a+4=0
X1.X2= c/a
2.X2= 5a+4/2
x2= 5a+4/4

x1+x2=-b/a
x1+x2= 3a-1/2

x1+x2=3a-1/2
2+5a+4/4=3a-1/2
2= 3a-1/2 - 5a+4/4
2= 6a-2-5a+4/4
2=a+2/4
8=a+2

a=6!!