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D = 0 atau b² - 4ac = 0
Jadi, nilai p = 5 atau p = 1.
a = 2p - 1
b = 5p - 1
c = 3p + 1
Akar kembar jika D = 0
D = b² - 4ac
0 = (5p - 1)² - 4((2p - 1) (3p + 1))
0 = 25p² - 10p + 1 - 4(6p² - p - 1)
0 = 25p² - 10p + 1 - 24p² + 4p + 4
0 = 25p² - 24p² - 10p + 4p + 1 + 4
0 = p² - 6p + 5
0 = p² - p - 5p + 5
0 = p(p - 1) - 5(p - 1)
0 = (p - 5) (p - 1)
p - 5 = 0
p₁ = 5
p - 1 = 0
p₂ = 1