Question

Jika log x + 2 log x^2 + 3 log x^3 = 3 log 6^3 + 5 log 3 - log 4, maka nilai x adalah

Answer 1

log x + 2 log x^2 + 3 log x^3 = 3 log 6^3 + 5 log 3 - log 4
Log x + Log (x²)² + Log (x³)³ = Log(6³)³ + Log3^5 - Log2²
Log x.x^4.x^9 = Log (6^9.3^5)/2²
Log x^14 = Log(2^9.3^9.3^5)/2²
14Logx = Log(2^7.3^14)
Log x = (1/14)Log(2^7.3^14)
Log x = Log (2^7.3^14)^(1/14)
     x    = (2^7.3^14)^(1/14)
           = 2^(1/2)(3)
           = 3√2