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*Ksp Mg(OH)2 = 4 x 10^-12
*Volume = 500 cm3 = 500 mL = 0,5 L
*Mr Mg(OH)2 = 58 g/mol
*Kelarutan (s) ?
Mg(OH)2 ⇔ Mg2+ + 2OH-
s 2s
Ksp = (s) (2s)^2
s = ∛10^-12
= 10^-4 mol/L
Dalam 10^-4 mol/L terdapat 10^-4 mol dalam 0,5 L, maka:
*n = g/Mr
g = 10^-4 mol x 58 g/mol
= 0,0058 gram
Maka, kelarutannya jika:
*Satuannya mol/L = 10^-4
*Satuannya g/L = 0,0058 g/L