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= √ ( 10^ -14 × 4,9 × 10^ -10) ÷ 1,8 × 10^ -5
= 5,2 × 10^ -10
pH = 10 - log 5,2
akar 10^-14/4,9 x 10^-10 * 1,8 x 10^-5
akar 0,36 x 10^-9
akar 3,6 x 10^-10
= 1,897 x 10^-5
ph = -log 1,897 x 10^-5
= 5 - log 1,897
maaf kalau terdapat kesalah, karena sedikit lupa yang dibagi Ka atau Kb, maf