Jawab:
f'(x) = 5x^4 - 2x + 3x^2
Penjelasan dengan langkah-langkah:
f(x) = (x^2 +1)(x^3-1)
f(x) = x^5 - x^2 + x^3 - 1
Penyelesaian:
f (x) = (x^2 + 1)(x^3 - 1)
misal
u = x^2 + 1
u' = 2x
v = x^3 - 1
v' = 3x^2
f'(x) = u'v + v'u
f'(x) = 2x(x^3 - 1) + 3x^2(x^2 + 1)
f'(x) = 2x^4 - 2x + 3x^4 + 3x^2
f'(x) = 5x^4 + 3x^2 - 2x
==================
Kelas: 11
Mapel: Matematika
Bab: Turunan Fungsi Aljabar
Kode: 11.2.9
Kata Kunci: Turunan pertama
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Verified answer
Jawab:
f'(x) = 5x^4 - 2x + 3x^2
Penjelasan dengan langkah-langkah:
f(x) = (x^2 +1)(x^3-1)
f(x) = x^5 - x^2 + x^3 - 1
f'(x) = 5x^4 - 2x + 3x^2
Penyelesaian:
f (x) = (x^2 + 1)(x^3 - 1)
misal
u = x^2 + 1
u' = 2x
v = x^3 - 1
v' = 3x^2
f'(x) = u'v + v'u
f'(x) = 2x(x^3 - 1) + 3x^2(x^2 + 1)
f'(x) = 2x^4 - 2x + 3x^4 + 3x^2
f'(x) = 5x^4 + 3x^2 - 2x
==================
Detil Jawaban
Kelas: 11
Mapel: Matematika
Bab: Turunan Fungsi Aljabar
Kode: 11.2.9
Kata Kunci: Turunan pertama