Jawab:
3x^2 + 12x
Penjelasan dengan langkah-langkah:
x^3 + 6x^2 + 2x + 5
dy/dx = 3x^2 + 12x + 2
dy/dx - 2 = 3x^2 + 12x + 2 - 2
dy/dx - 2 = 3x^2 + 12x
saling koreksi ya kalo salah :)
Penyelesaian:
y = x^3 + 6x^2 + 2x + 5
y' = 1.3x^2 + 2.6x + 2 + 0
y' = 3x^2 + 12x + 2
y'(-2) = 3(-2)^2 + 12(-2) + 2
y'(-2) = 12 - 24 + 2
y'(-2) = - 10
==================
Kelas: 11
Mapel: Matematika
Bab: Turunan Fungsi Aljabar
Kode: 11.2.9
Kata Kunci: Turunan pertama
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Verified answer
Jawab:
3x^2 + 12x
Penjelasan dengan langkah-langkah:
x^3 + 6x^2 + 2x + 5
dy/dx = 3x^2 + 12x + 2
dy/dx - 2 = 3x^2 + 12x + 2 - 2
dy/dx - 2 = 3x^2 + 12x
saling koreksi ya kalo salah :)
Penyelesaian:
y = x^3 + 6x^2 + 2x + 5
y' = 1.3x^2 + 2.6x + 2 + 0
y' = 3x^2 + 12x + 2
y'(-2) = 3(-2)^2 + 12(-2) + 2
y'(-2) = 12 - 24 + 2
y'(-2) = - 10
==================
Detil Jawaban
Kelas: 11
Mapel: Matematika
Bab: Turunan Fungsi Aljabar
Kode: 11.2.9
Kata Kunci: Turunan pertama