Question

Jika fungsi f sedemikian sehingga f(0)= 5 , f(1) =2 dan f(n+2)=2f(n)+f(n+1) , maka f(2) sama dengan .......

Answer 1

F (0)=5 dan f (1)=2
f (n+2)=2f (n)+f (n+1)
f (0+2)=2f(0)+f (0+1)
f(2) = 2f(0)+f (1)
f (2) = 2.5 + 2
f (2) = 12