Question

Jika fungsi f sedemikian sehingga f(0)= 3, f(1)= 5 dan f(n+2)=2f(n+1)+3f(n) , maka f(3) sama dengan .......

Answer 1

F (0)=3
f (1)=5
f (n+2) = 2f(n+1) + 3f (n)
f (0+2) =2f(0+1)+3f (0)
f (2) = 2f (1) + 3f(0)
= 2.5 + 3.3
= 10 + 9
= 19
f (1+2)=2f (1+1)+3f (1)
f (3) = 2f (2) + 3f(1)
= 2. 19 + 3 . 5
= 38 + 15
= 53