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3f ' (3x + 2) = √(x + 1) + x/(2√(x + 1))
utk x = 3 maka
3f ' (11) = √4 + 3/(2√4)
3f ' (11) = 2 + 3/4
3f ' (11) = 11/4 (kedua ruas kalikan 4)
12f ' (11) = 11