Question

Jika diketahui 7log 2 = a dan 2log 3 = b,maka nilai 6log 98 adalah ?

Answer 1

2'log 98 / 2'log 6
= 2'log (2 x 7^2) / (2'log 2 x 3)
= (1 + 2 x 2'log 7) / (2'log 2 + 2'log 3)
= (1 + 2/a) / (1 + b) kalikan a/a
= (a + 2)/(a + ab)