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y + 3x = 3 ...(1)
x'log (x + 12)/64 = -1
(x + 12)/64 = 1/x
x² + 12x - 64 = 0
(x + 16)(x - 4) = 0
x = -16 atau x = 4
ambil yg x = 4
maka y + 12 = 3
y = -9
x + 2y = 4 - 18
= -14