Question

.
Jika bc - 2b = 1
ab - a = 1
ac - 3c = 1

maka nilai abc = . . .

Answer 1

Jika bc - 2b = 1 -----> b ( c - 2) = 1 ---> a = 1/(c-2)
ab - a = 1         ------>. a( b -1) = 1 ----> b = 1/(b-1)
ac - 3c = 1       ------> c( a - 3) = 1 -----> c = 1/(a-3)
a.b.c = {1/(c-2)}{1/(b-1)}{1/(a-3)}
        = 1/(abc - 3bc + 6b - ac + 3c -2ab + 2a - 6)
        = 1/{abc - 3(bc- 2b) -(ac - 3c) - 2 (ab - a) - 6}
        = 1/{abc - 3 - 1 -2 - 6)
        = 1(abc - 12)
(abc)^2 - 12(abc) = 1
 (abc)^2 - 12(abc) + 36 = 1 + 36
(abc - 6)^2 = 37
abc - 6 = √37
abc = 6 + √37
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