Question

Jika 3Long 4 =a dan 3lina 5=b tentukan nilai 12 long 20

Answer 1

3log4=a
log4/log3=a
log4=alog3

3log5=b
log5/log3=b
log5=blog3

12log20=log20/log12
=(log(4.5))/(log(4.3))
=((log4)+(log5))/((log4)+(log3))
=((alog3)+(blog3))/((alog3)+(log3))
=(log3(a+b))/(log3(a+1))
=(a+b)/(a+1)