Question

Jika 2log3=a dan 3log4=b, maka tentukan 18log12

Answer 1

²log 3 = a
³log 4 = b
²log3 × ³log 4 = ab
²log 4 = ab
²log2² = ab
2 = ab

^18 log 12 = ³log12 / ³log 18
^18 log 12 = (³log3+³log4)/(³log3²+³log2)
^18 log 12 = (1 + b)/(2(1) + 1/a)
^18 log 12 = (1 + b)/((2a + 1)/a)
^18 log 12 = (a + ab)/(2a + 1)