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HCl -> H⁺ + Cl⁻
0,1 M 0,1M 0,1M
ph (H⁺) = -log (H⁺)
= - log (10⁻¹)
= -(-1) log 10
ph (H⁺) = 1
NaOH -> Na⁺ + Cl⁻
0,1 M 0,1M 0,1M
ph (OH⁻) = - log (OH⁻)
= - log (10⁻¹)
= -(-1) log 10
ph (OH⁻) = 1
ini jawaban menurut saya kalo salah mohon maaf saya juga sedang belajar