berarti reaksinya
3Ca(Nao3)2 + 2Na3Po4 --> Ca3(Po4)2 + 6NaNo3
awal. 1 2
reaksi 1 0,67 0,33. 2
sisa. - 1,33 . 0,33. 2
endapannya berarti Ca3(Po4)2 ..
Jmlah Atom Ca = 3
Jmlah atom P = 2
Jumlah atom O = 8
Mr Ca3(PO4)2 =
3..Ar Ca + 2.Ar P + 8.Ar O =
3 .40 + 2 . 31 + 8.16 =
310 gr
massa endapan = 0,33 x 310 = 102,3 gr
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berarti reaksinya
3Ca(Nao3)2 + 2Na3Po4 --> Ca3(Po4)2 + 6NaNo3
awal. 1 2
reaksi 1 0,67 0,33. 2
sisa. - 1,33 . 0,33. 2
endapannya berarti Ca3(Po4)2 ..
Jmlah Atom Ca = 3
Jmlah atom P = 2
Jumlah atom O = 8
Mr Ca3(PO4)2 =
3..Ar Ca + 2.Ar P + 8.Ar O =
3 .40 + 2 . 31 + 8.16 =
310 gr
massa endapan = 0,33 x 310 = 102,3 gr