jesli liczbe (5-2√3)^3 zapisano w postaci a+bV3 gdzie a ib należa do C to:A.b=-20B.b=-54C.b=-150D.b=-174
(a-b)³ = a³ - 3a²b + 3ab² -b³
(5-2√3)³ = 5³ - 3*5²*2√3 + 3*5*(2√3)² -(2√3)³ =
= 125 - 75*2√3 + 15* 12 - 2√3*2√3*2√3=
= 125 - 150√3 + 180 - 24√3 =
= 305 - 174√3
a + b√3
więc;
b=-174 odp. D
Odp.: D.
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(a-b)³ = a³ - 3a²b + 3ab² -b³
(5-2√3)³ = 5³ - 3*5²*2√3 + 3*5*(2√3)² -(2√3)³ =
= 125 - 75*2√3 + 15* 12 - 2√3*2√3*2√3=
= 125 - 150√3 + 180 - 24√3 =
= 305 - 174√3
a + b√3
więc;
b=-174 odp. D
Odp.: D.