March 2019 0 21 Report
Jeżeli 0° < \alpha < 90° oraz tg \alpha = 8 sin\alpha (1 - sin^{2} \alpha) , to:
A) cos \alpha = \frac{1}{4}
B) cos \alpha = 1
C) cos \alpha = \frac{\sqrt{2} }{2}
D) cos \alpha = \frac{1}{2}

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