Wzór na pole rombu
P = (1/2)*e*f
zatem
(1/2)*10*f = 40
5*f = 40
f = 40 : 5 = 8
f/2 = 4
e/2 = 5
a^2 = 4^2 + 5^2 = 16 + 25 = 41
a = p(41)
Obwód rombu L = 4*a = 4*p(41)
==================================
p(41) -- pierwiastek kwadratowy z 41
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Wzór na pole rombu
P = (1/2)*e*f
zatem
(1/2)*10*f = 40
5*f = 40
f = 40 : 5 = 8
f/2 = 4
e/2 = 5
a^2 = 4^2 + 5^2 = 16 + 25 = 41
a = p(41)
Obwód rombu L = 4*a = 4*p(41)
==================================
p(41) -- pierwiastek kwadratowy z 41