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Verified answer
Materi LogaritmaNumerusnya sudah sma, jadi basisnya yang perlu disamakan
x^2 + 6x = 2x + 5
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 atau x = 1
Ketika x = -5, basis akan bernilai negatif shg tak terdefinisi. Ambil x = 1.
Verified answer
(x² + 6x)'log (1/3) = (2x + 5)'log (1/3)x² + 6x = 2x + 5
x² + 6x - 2x - 5 = 0
x² + 4x - 5 = 0
(x - 1)(x + 5) = 0
x - 1 = 0 ---> x = 1
atau
x + 5 = 0 ---> x = -5 (tdk memenuhi)
Nilai x yg memenuhi soal :
x = 1