∠ACD = ∠ABD - ∠BDC
30° = 7x° - 4x°
30° = 3x°
x = 30°/3
x = 10°
∠AOD
= 2 x ∠ABD
= 2 x 7x°
= 2 x 7(10°)
= 2 x 70°
= 140°
→ sudut ←
∠DBC + ∠BDC + ∠ACD = 180°
180° - ∠ABD + 4x + 30° = 180°
-7x + 4x = -30
-3x = -30
x = 10
= 2 × ∠ABD
= 2 × 7x
= 140° ✔
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Verified answer
∠ACD = ∠ABD - ∠BDC
30° = 7x° - 4x°
30° = 3x°
x = 30°/3
x = 10°
∠AOD
= 2 x ∠ABD
= 2 x 7x°
= 2 x 7(10°)
= 2 x 70°
= 140°
→ sudut ←
∠DBC + ∠BDC + ∠ACD = 180°
180° - ∠ABD + 4x + 30° = 180°
-7x + 4x = -30
-3x = -30
x = 10
∠AOD
= 2 × ∠ABD
= 2 × 7x
= 140° ✔