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[a11 a12 a13]
[a21 a22 a23]
[a31 a32 a33]
cara mencari adjoin
Adj A, negatif dan positif bergantian
[+[a22 a23]…-[a12 a13]…+[a12 a13]
[..[a32 a33]….[a32 a33]…..[a22 a23]
[………………………………………..]
[- [a21 a23]...+[a11 a13]…-[a11 a13]
[..[a31 a33]….[a31 a33]…..[a21 a23]
[………………………………………..]
[+[a21 a22]…-[a11 a12]...+[a11 a12]
[..[a31 a32]….[a31 a32]…..[a21 a22]
det C = (2 . - 3 .1 + 1 .2 .3 + 1 .0 .2) - (1 .0 .1 + 2 .2 .2 + 1 . - 3 .3)
= (- 6 + 6 + 0) - (0 + 8 - 9)
= 0 - (- 1)
= 1
det. D = (2 .- 3 . 1 + 2 .1 .2 + 3 .1 .- 1) - (2 .1 .1 + 2 .1 .- 1 + 3 .- 3 .2)
= (- 6 + 4 - 3) - (2 - 2 - 18)
= - 5 - (- 18)
= - 5 + 18
= 13