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Dane:
10% - st. I roztowru
60% - st. II roztowru
600- masa roztworu 20%
20%- st. III roztworu
Sz: masa roztworu I i II
0.1x+ 0.6y= 0.2× 600
x+y=600
0.1(600-y)+ 0.6y=120
60-0.1y+0.6y=120
0.5y=60
y=120
x=480