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70g 1 mol
2(NH3 *H2O)+ H2SO4 --->(NH4)2SO4 + 2H2O
xg 0,0282mola
Vr H2SO4=28,2cm3=0,0282dm3
Cm=1,0M
n=Cm*Vr=1,0mol/dm3*0,0282dm3=0,0282mola
x=0,0282mola*70g=1,974g (ms)
Cp=ms*100%/mr=1,974g*100%/28.2g
Cp=7%