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r=10cm
2πr=2π×10=20πcm
h=10cm
l=a√2=10√2cm
wycinek koła:
r=10√2cm
łuk=20πcm
łuk=α:360×2πr
20π=α:360×2πr/:2π
10=α:360×10√2
α×10√2=3600
α=3600:10√2=360√2:2=180√2⁰(= około 253,8⁰)