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1/ dane: pH = 4, Ka = 1,8*10^-5, pKa = 4,75
pH = pKa + log c sól/c kwas
4 = 4,75 + logc sól/c kwas
logc sól/c kwas = - 0,75
c sól/c kwas = 0,18
2/ dane: pH = 9,8, Ka2 = 4,4*10^-11, pKa2 = 10,36
logc sól/c kwas = pH - pKa2 = 9,8 - 10,36 = - 0,56 = log 0,275
c sól/c kwas = 0,275
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