Jaka jest masa próbki siarki zawierająca tyle samo atomów co 5,6żelaza
mFe=56u
56g Fe------6,02*10^23 at.
5,6g Fe--------x at.
x = 0,6*10^23 at.
mS=32u
32g S------6,02*10^23 at.
xg S---------0,6*10^23 at.
x = 3,2g S
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mFe=56u
56g Fe------6,02*10^23 at.
5,6g Fe--------x at.
x = 0,6*10^23 at.
mS=32u
32g S------6,02*10^23 at.
xg S---------0,6*10^23 at.
x = 3,2g S