jak w załaczniku chodzi o zadanie 4 (prosze o dokladne rozwiazania)
√a=0,2 /²
a=0,2²
a=0,04
∛b=-1⅓ /³
b=(-4/3)³
b=-64/27
⁴√x=√3² /⁴
x=(√9)⁴
x=3⁴
x=81
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√a=0,2 /²
a=0,2²
a=0,04
∛b=-1⅓ /³
b=(-4/3)³
b=-64/27
⁴√x=√3² /⁴
x=(√9)⁴
x=3⁴
x=81